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Avoid http URL String (making checkstyleNohttp happy)

See gh-33561
pull/33720/head
Juergen Hoeller 1 year ago
parent
commit
49da92b6a3
  1. 12
      spring-core/src/test/java/org/springframework/core/io/ResourceTests.java

12
spring-core/src/test/java/org/springframework/core/io/ResourceTests.java

@ -380,8 +380,8 @@ class ResourceTests { @@ -380,8 +380,8 @@ class ResourceTests {
@Test
void unusualRelativeResourcesAreEqual() throws Exception {
Resource resource = new UrlResource("file:dir/");
Resource relative = resource.createRelative("http://spring.io");
assertThat(relative).isEqualTo(new UrlResource("file:dir/http://spring.io"));
Resource relative = resource.createRelative("https://spring.io");
assertThat(relative).isEqualTo(new UrlResource("file:dir/https://spring.io"));
}
@Test
@ -422,14 +422,14 @@ class ResourceTests { @@ -422,14 +422,14 @@ class ResourceTests {
@Test
void useUserInfoToSetBasicAuth() throws Exception {
startServer();
UrlResource resource = new UrlResource("http://alice:secret@localhost:"
+ this.server.getPort() + "/resource");
UrlResource resource = new UrlResource(
"http://alice:secret@localhost:" + this.server.getPort() + "/resource");
assertThat(resource.getInputStream()).hasContent("Spring");
RecordedRequest request = this.server.takeRequest();
String authorization = request.getHeader("Authorization");
assertThat(authorization).isNotNull().startsWith("Basic ");
assertThat(new String(Base64.getDecoder().decode(
authorization.substring(6)), StandardCharsets.ISO_8859_1)).isEqualTo("alice:secret");
assertThat(new String(Base64.getDecoder().decode(authorization.substring(6)),
StandardCharsets.ISO_8859_1)).isEqualTo("alice:secret");
}
@AfterEach

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